Dynamic forces exerted by fluid on plate normal to jet
Dynamic force exerted by fluid on stationery inclined plate
Force exerted by jet on stationery curved plate
Force exerted on moving plate held normal to plate
Let a fluid of density ρ
moving with velocity V be striking a
plate moving in the same direction with the velocity of u.
plate moving in the same direction with the velocity of u.
So, relative velocity of jet = V-u
And mass of fluid striking jet per second
= ρa(V-u)
Force exerted by jet = mass of fluid
striking per sec * change
in velocity
= ρa(V-u)*(V-u – 0)
=ρa(V-u)2
in velocity
= ρa(V-u)*(V-u – 0)
=ρa(V-u)2
Force exerted on moving plate held inclined in the direction normal to the plate
The
angle between the jet and plate is θ as
shown in the
figure.
figure.
Relative
velocity with which jet strikes the plate is (V-u)
Mass
of fluid striking plate per second is ρa(V-u)
Force exerted in the direction normal to the plate is ρa(V-u)[(V-u)sinθ-0]
Force exerted in the direction normal to the plate is ρa(V-u)[(V-u)sinθ-0]
Fn = ρa(V-u) 2sinθ
Component
of this force in the direction of jet = Fn sinθ
= ρa(V-u) 2sin2θ
= ρa(V-u) 2sin2θ
Force exerted on curved plate moving along
direction of jet
Let,
V be the absolute velocity of the jet, a be the area of jet
and u be the velocity of the vane in the direction of jet.
and u be the velocity of the vane in the direction of jet.
So,
relative velocity of the jet is (V-u) and after striking the
component of this velocity in the direction of jet is -(V-u)cosθ
(opposite in direction) as shown in figure.
component of this velocity in the direction of jet is -(V-u)cosθ
(opposite in direction) as shown in figure.
Mass
of fluid striking the plate per second = ρa(V-u)
Force
exerted by the jet in the direction of jet = ρa(V-u)[(V-u)-{-(V-u)
cosθ}]
= ρa(V-u)2(1+ cosθ)
What is the use of stationery plate in mechanical engineering?
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